Math, asked by sonijagu555, 10 months ago

lim
 {x }^{2}  - 2x - 3 \div x - 3

Answers

Answered by Anonymous
2

Solution

 = lim \frac{x {}^{2} - 2x - 3 }{x - 3}  \\  = lim \frac{x {}^{2}  - 3x + x - 3}{x - 3}  \\  = lim \frac{x (x - 3) + 1(x - 3)}{x - 3}  \\  = lim \frac{(x - 3)(x + 1)}{(x - 3)}  \\  = >  lim(x + 1)  = (0 + 1) = 1\\  \:  \:  \:  \:  \:  \:  \:  \: x→0

Answered by Atharvgovardhan
0

Step-by-step explanation:

x^2-2x-3/x-3

x^2(x-3)/x-3-2x(x-3)/x-3-3/x-3

x^3-3x^2-2x^2-6x-3/x-3

x^3-5x^2-6x-3/x-3

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