Math, asked by Suman937447, 1 year ago

Lim(u trends to 0) then 3u^-2u/u=?

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Answered by Anonymous

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Answered by Steph0303

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$\lim_{u \to \0} \:\: \dfrac{3u^2 - 2u}{u}\\\\\text{Taking common terms in the numerator, we get,}\\\\\lim_{u \to 0} \:\: \dfrac{ u(3u - 2) }{u}\\\\\text{ 'u' gets cancelled. Hence we get,}\\\\\lim_{u \to 0} \:\: ( 3u - 2 )\\\\\text{Applying limits we get,}\\\\\implies 3 ( 0 ) - 2 \\\\\implies 0 - 2 \\\\\implies - 2\\\\\text{Hence the answer is -2.}$

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Lim(u trends to 0) then 3u^-2u/u=?