Question

lim x → 0 1-cos5x+tan3x/sin2x

Answer 1

Answer:

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Step-by-step explanation:

limx→01−cos(x)x=0

Then we have as follows.

limx→01−cos(5x)+tan(3x)sin(2x)=limx→01−cos(5x)sin(2x)+limx→0tan(3x)sin(2x)=52⋅limx→01−cos(5x)5x⋅limx→02xsin(x)+limx→0sin(3x)cos(3x)sin(2x)=0+32⋅limx→0sin(3x)3x⋅limx→02xsin(2x)⋅limx→01cos(3x)=32