Math, asked by bkangar08, 1 year ago

Lim x-0 3x²/(1-cos5x)

Answers

Answered by Sunil1124
0

Lim 3x^2/ 1 - cos 5x

x-0


Lim. 6x/sin5x. ( by L hospital rule)

x-0


Lim 6x / sin5x × 5x/5x. ( divide and

x-0

multiply by 5x)


Lim. 6x/5x

x-0


Lim. 6/5

x-0


6/5

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