Math, asked by priyanshisengar43, 7 months ago

lim x-0
[ax+xcosx/bsinx]

Answers

Answered by Rajan1806

1

Answer:

Ans. - a+1/b

Step-by-step explanation:

lim x-0

ax+xcosc/bsinx

= lim x-0 ax/x + xcosx/x / bsinx/x

= lim x-0 a+ cosx / b(1) (sinx/x=1)

= a + cos 0 / b ( putt the value of x )

= a + 1 / b

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