lim x=0 Cos ax -cos bx / cos cx - cos dx
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Refer to the image attachment for the answer
Step-by-step explanation:
First we apply the identity of cos2x and convert the entire equation in the form of sin.
Next, we take 2 common out and cancel it.
Then we multiply both the numerator and denominator by the squares of bx/2, ax/2, cx/2 and dx/2 respectively as and when required as given in the solution.
As we know that sinx / x when
lim x->0 is 1, we we can cancel them out to make 1.
Next we open the squares of the remaining variables and cancel out 4 and x square from the remaining equation and get the last three steps mentioned in the last line.
If it helped then please mark the brainliest..
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