Question

lim x→0 (cot x)^sin 2x​

Answer 1

Answer:

Step-by-step explanation:

lim x tends to 0 (cot x)^sin 2x

apply e^ lim x tends to 0 power log  base

applying we get

e^lim  x tends to 0  sin 2x log cot x

e^lim  x tends to 0 2x sin 2x/2x log cot x

we know lim x tends  sin 2x /2x =1

e^lim  x tends to 0 2x log cot x

e^lim  x tends to 0 2x log (cos x /sin x)

e^lim  x tends to 0 2x(log cos x - log sin x)

e^lim  x tends to 0  2x log cos x - 2x log sin x

e^0

1