Math, asked by trigoinlim, 1 year ago

lim x-0 tanx-sinx/sin*3

Answers

Answered by chandujadhav
1
The answer is...........

lim x-0 tanx - sinx/sin^3

dividing num and deno by x

Lim x -0 [ ( tanx - sinx )/ x ] / [ (sinx^3 )/x]

lim x-0 [ tanx / x - sinx / x ] / [ sinx / x ]^3 x^2

[ tanx / x = 1 , sinx / x =1 ]

lim x-0 [ ( 1 - 1 ) ]/ ( 1)^3 • x^2

Lim x -0 [ ( 0 )] / ( 1) • x^2

taking limit

= o/0

= 0

answer is 0

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