Math, asked by ayushbisht097, 24 days ago

lim {(x+1)^5-1}/x
x->0

Answers

Answered by jitendra12iitg
0

Answer:

The answer is 5

Step-by-step explanation:

                  Formula to be used :

                   \boxed{\displaystyle\lim_{x\to a}\dfrac{x^n-a^n}{x-a}=na^{n-1}}

Given limit

                    \displaystyle \lim_{x\to 0}\dfrac{(x+1)^5-1}{x}

Substitute x+1=t \Rightarrow If x=0  then t=1

                   =\displaystyle \lim_{t\to 1}\dfrac{t^5-1}{t-1}

                   =5(1)^{5-1}=5(1)^4=5(1)=5

                    ( using above formula )

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