Lim x--1 (x^431+3*x^221−2*x^39−2)/(x-1)
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Answer:
apply L Hospital's rule
Step-by-step explanation:
(1+3-2-2)/1-1
which is 0/0 form
apply L Hospital's rule
lim x--1 (431x^430+663x^220-78^38-0)/1-1
apply the limit
431+663-78=1016
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