Math, asked by Dhoni1916, 8 months ago

Lim x--1 (x^431+3*x^221−2*x^39−2)/(x-1)

Answers

Answered by harimoorthy2002
1

Answer:

apply L Hospital's rule

Step-by-step explanation:

(1+3-2-2)/1-1

which is 0/0 form

apply L Hospital's rule

lim x--1 (431x^430+663x^220-78^38-0)/1-1

apply the limit

431+663-78=1016

Similar questions