lim x=1 x3- 3x +1/ x-1
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We have,
x→1
lim
x−1
x
3
−3x+1
Let L=
x→1
lim
x−1
x
3
−3x+1
This is
0
0
form.
So, apply L-Hospital rule,
=
x→1
lim
1−0
3x
2
−3+0
=
x→1
lim
1
3x
2
−3
=
x→1
lim
3x
2
−3
=3(1)
2
−3
L=3−3=0
Hence, this is the answer.
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