Question

lim x^10-1024/x^5-32 when x tends to 2​

Answer 1

Answer:

x^10 - 1024 = (x^5)^2 - (2^5)^2 = (x^5 - 2^5 )(x^5 + 2^5)

so given term = lim x tends to 0 (x^5 - 2^5 )(x^5 + 2^5) /(x^5 - 2^5 ) = lim x tends to 0 (x^5 + 2^5) = 2^5

Answer 2

Answer:

64

Step-by-step explanation:

this can be written as

lim x--> 2 ((x^10-2^10)/(x-2))*((x-2)/(x^5-2^5))

10 × 2^9/5x 2^4

=2×2^5

=2^6= 64

note that we have used formula lim x--> a (x^n-a^n)/(x-a)=na^(n-1)