Math, asked by tausifh703, 1 year ago

lim x=π/2 tan2x/x-π/2​

Answers

Answered by Vikassandeep
3

Answer:

Step-by-step explanation:

Attachments:
Answered by llSecreTStarll
10

Solution :

 \sf \underset{x \longrightarrow \:  \frac{ \pi}{2} }{lim} \:  \:  \frac{tan2x}{x -  \frac{ \pi}{2} }  \\  \\

Let h = x - π/2

\sf \underset{h\longrightarrow \:  0 }{lim} \:  \:  \frac{tan2x}{h}  \\  \\ \sf \underset{h \longrightarrow \:  0 }{lim} \:  \frac{ tan \: 2(h +  \frac{ \pi}{2} )}{h} \\  \\ \sf \underset{h \longrightarrow \:  0 }{lim} \:  \:  \frac{tan \: (2h +  \pi)}{h}  \\  \\ \sf \underset{h \longrightarrow \:  0 }{lim} \:  \:  \frac{tan \: ( \pi + 2h)}{h}  \\  \\ \sf \underset{h\longrightarrow \:  0}{lim} \:  \:  \frac{tan2h}{h}  \\  \\ \sf \underset{h\longrightarrow \:  0 }{lim} \:  \:  \frac{tan \: 2h}{h \times  \frac{2}{2} }  \\  \\ \sf \underset{h\longrightarrow \:  0 }{lim} \:  \: \frac{tan2h}{2h \times  \frac{1}{2} }  \\  \\ \red{\boxed{ \sf\underset{h\longrightarrow \:  0 }{lim} \:  \: \frac{tan \: x}{x}  = 1}} \\  \\  = 1 \times 2 \\  \\  = 2

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