Math, asked by pkkp, 1 year ago

lim x → 2 (x^3- 3x^2 + 4)/(x^4-8x^2+16)
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Answers

Answered by zdm786
12
Lim x → 2 (x^3- 3x^2 + 4)/(x^4-8x^2+16)
=
Lim x → 2 d/dx(x^3- 3x^2 + 4)/d/dx(x^4-8x^2+16)
=Lim x → 2  3x^2-6x/4x^3-16x
=Lim x → 2  d/dx(3x^2-6x)/d/dx(4x^3-16x)
=Lim x → 2  (6x-6)/(12x^2-16)
=(6*2-6)/(12*4-16)
=12-6/48-16
=6/32
=3/16 ans
Answered by Abhinav200
6
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