Math, asked by muskanjain2510, 1 month ago

lim x → 3π/2 (3π/2-x)tan x​

Answers

Answered by vipinkumar212003
0

Answer:

 \lim_{x \rightarrow \frac{3\pi}{2} }( \frac{3\pi}{2 - x} ) \tan x \\  = ( \frac{3\pi}{2 - \frac{3\pi}{2}} ) \tan \frac{3\pi}{2} \\  = ( \frac{6\pi}{4 - 3\pi} ) \tan (\pi  +  \frac{\pi}{2} ) \\   = ( \frac{6\pi}{4 - 3\pi} ) \cot \frac{\pi}{2} \\ = ( \frac{6\pi}{4 - 3\pi} ) \times 0 \\  = 0 \\  \\  \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}

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