lim
x-π/3. 4sin²x - 3/8cos³x-1. =-2/3
Answers
Answered by
0
lim
x→
3
π
2cosx−1
sin(
3
π
−x)
This is a [
0
0
] form.
so we can apply the L-Hospital's rule.
lim
x→
3
π
−2sinx
−cos(
3
π
−x)
=lim
x→
3
π
2sinx
cos(
3
π
−x)
=
2sin
3
π
cos(
3
π
−
3
π
)
=
2.
2
3
cos0
=
3
1
Answered by
0
lim
x-π/3. 4sin²x - 3/8cos³x-1. =125/64
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