Question

lim

x→4

3 − x

x2 − 2x − 8​

Answer 1

Eight different resistors of 1Ω, 2Ω, ... , 8Ω are connected in parallel across a battery of 10V.

We have to find current flow in 1Ω resistor.

\star⋆ We know that, potential difference across each resistor remains same in parallel connection.

Therefore potential difference across all eight resistors will be 10V.

We have asked to find current flow in 1Ω resistor.

\star⋆ As per ohm's law, current flow in resistor is directly proportional to the applied potential difference. (at constant temperature)

V = IR

V denotes voltage of battery

I denotes current

R denotes resistance

By substituting the values,

➝ V = I × R

➝ 10 = I × 1

➝ I = 10/1

➝ I = 10A

∴ 10A current will flow in resistor of 1Ω.