Math, asked by ayushigautam0414, 10 months ago

lim x → π/4 sec^2x -2/tanx-1

Answers

Answered by 217him217
3

Answer:

lim x->π/4 (sec²x-2)/(tanx-1)

lim x->π/4 (sec²x - 1 -1 )/(tanx-1)

lim x->π/4. (tan²x -1)/(tanx-1)

limx->π/4. (tanx-1)(tanx+1)/(tanx-1)

lim x->π/4 (tanx+1)

put limit

(tan(π/4) + 1)

1+1

=2

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