Question

lim x cos x - log (1+x)
x-0 _____________
x²​

Answer 1

Answer:

Answer

We have,

x→0

lim

x

2

xcosx−log(1+x)

Applying L’ Hospital rule and we get,

x→0

lim

2x

x(−sinx)+cosx−

1+x

1

⇒

x→0

lim

2

x(−cosx)+(−sinx)−sinx+

(1+x)

2

1

Taking limit and we get,

2

0+0−0+

(1+0)

2

1

=

2

1