Question

lim X->0 (1-cos3X) ÷x²​

Answer 1

Answer:

Step-by-step explanation:

Given limit

x→0lim​x2(1−cos3x)​

=x→0lim​(23x​)2×94​2sin2(23x​)​=29​.

Answer 2

Answer:

9/2

Step-by-step explanation:

limx->0 d/dx(1-cos3x)÷d/dx(x²)

limx->0 3sin3x÷2x

apply the constant multiple rule

limx->0cf(x)=climx->0f(x)

3limx->0sin(3x)/x÷2

apply LHS rule

therefore

limx->0(1-cos3x)÷x²=9/2