Question

Lim x->0 [cosx+a³sin(b^6x)]^1/x = e^512 .find the value of ab²

Answer 1

Answer:

value of ab² = 8³

Step-by-step explanation:

Lim (1+casx+a3 sin (b6x) - 1)0

x = 0

casx +a3 sin (b6x)-1

          x

Lim  1-x2  + b6 a3               sin (b6x)  - 1/x

         2                                    xb6

          x

l b6 a3 = l512

b6 a3 = 512

(AB2)3 = 8³