Question

lim x->1/2 (32x^5-1/8x^3-1)​

Answer 1

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$\underline{\underline{\blue{Given}}}$

$x \: = \frac{1}{2}$

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$\underline{\underline{\green{To\:find}}}$

$= \frac{32 {x}^{5} - 1}{8 {x}^{3} - 1 } \\ = \frac{ 32 \times \frac{1}{ {2}^{5} } - 1}{8 \times \frac{1}{ {2}^{3} } - 1} \\ = \frac{ 32 \times \frac{1}{32} - 1}{8 \times \frac{1}{8} - 1} \\ = \frac{ 1 - 1}{1 - 1} \\ = \frac{0}{0} = 0$

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