Question

lim x->π/2 (1-sinx)/cosx​

Answer 1

Answer:

lim  cosx/(1-sinx)

x->π/2

L'Hopital's rule:

-sinx/-cosx

as x->π/2 then -sin(π/2)/-cos(π/2) =>-1/0 =>-∞

simple as that

Step-by-step explanation:

Answer 2

Answer:

It's easy...

Step-by-step explanation:

Check the attachment for your answer

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