Question

lim x----> infinity sin


Plz give with proper explanation....​

Answer 1

As #x# approaches infinity, the #y#-value oscillates between #1# and #-1#; so this limit does not exist.

Thus, the answer is it DNE (does not exist).

One good rule to have while solving these problems is that generally, if there is no #x# in the denominator at all, then the limit does not exist.

Example:

#lim_(x->oo)sinx=DNE#

#lim_(x->oo)(sinx)/(x)=0# (Squeeze Theorum

Answer 2

Answer:

As x approaches infinity, the y -value oscillates between 1 and −1 ; so this limit does not exist.