lim(x->pi/4) (log(cotx))/(pi-4x)
Answers
Answered by
0
lim (x--> pi/4)(log (cotx))/(pi-4x)
first put x-pi/4=h
then lim(h--> 0)(log (cot (h+pi/4)/(pi-4h-pi)
=> lim(h--> 0)(log(cot (pi/4+h))/-4h
=>(-1/4) lim (h--> 0) log(cot (pi/4+h))/h
=>(-1/4) lim (h--> 0)(cot(pi/4+h)-1)/h
=>(-1/4) lim (h--> 0)(-tan (pi/4+h)/1
=> 1/4
first put x-pi/4=h
then lim(h--> 0)(log (cot (h+pi/4)/(pi-4h-pi)
=> lim(h--> 0)(log(cot (pi/4+h))/-4h
=>(-1/4) lim (h--> 0) log(cot (pi/4+h))/h
=>(-1/4) lim (h--> 0)(cot(pi/4+h)-1)/h
=>(-1/4) lim (h--> 0)(-tan (pi/4+h)/1
=> 1/4
abhi178:
please mark as brainliest
no 0.5 is the ans
yes you are right
in second last step I was wrong .
>cot (pi/4+h)-1}/h gain 0/0 in h---> 0
h----> 0
differentiate nominator and denominator w.r.t h
i.e (-1/4) (-cosec^2 (pi/4+h)/1
now put value h--> 0 you got answer is 1/2
Similar questions