Math, asked by ayushigautam0414, 9 months ago

lim x^m -1/x^n -1
x → 1

Answers

Answered by 217him217
2

Answer:

lim x->1 (x^m-1)/(x^n-1)

using Leibniz rule

= limx->1 (mx^(m-1))/ (nx^(n-1))

put x= 1

=m*(1)^(m-1) / n*(1)^(n-1)

= m/n

Answered by gargs4720
0

Answer:

LIM x>1(x^m-1)/(x^n-1)

USING LEBENIZ RULE

=limx->1(mx^(m-1))/nx^(n-1))

PUT x=1

=m*(1)^(m-1)/n*(1)^(n-1)

=m/n

HOPE IT MAY HELPS YOU!

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