lim x^m -1/x^n -1
x → 1
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Answered by
2
Answer:
lim x->1 (x^m-1)/(x^n-1)
using Leibniz rule
= limx->1 (mx^(m-1))/ (nx^(n-1))
put x= 1
=m*(1)^(m-1) / n*(1)^(n-1)
= m/n
Answered by
0
Answer:
LIM x>1(x^m-1)/(x^n-1)
USING LEBENIZ RULE
=limx->1(mx^(m-1))/nx^(n-1))
PUT x=1
=m*(1)^(m-1)/n*(1)^(n-1)
=m/n
HOPE IT MAY HELPS YOU!
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