Lim x tans to 3 { 1÷(x-3) - 1÷(x-3)(x-2)}
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Hi mate!!
By putting Lt x->3 directly we get 0/0 form so, by using L- Hospitals rule
Which says differentiate numnator and denominator separately.
3 / (x-3) {1 - (x-2)}
-3
By putting Lt x->3 directly we get 0/0 form so, by using L- Hospitals rule
Which says differentiate numnator and denominator separately.
3 / (x-3) {1 - (x-2)}
-3
manishpurve123:
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