lim x tending to n { x }
where { . } represents fractional part function
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ANSWER
(1.)LHL=lim
h→0
(f(
2
π
)−h)
=lim
h→0
(sin[(
2
π
)−h)]
=lim
h→0
[cosh]=0
RHL=lim
h→0
(f(
2
π
)+h)
=lim
h→0
[sin(
2
π
)+h)]
=lim
h→0
[cosh]=0
∴LHL=RHL=0
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