Math, asked by syedyunus326pany96, 1 year ago

lim x tends 0 1/(x-a)^2​


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Answers

Answered by manish5365
0
 \binom{lim}{x - > 0} \frac{1}{ {(x - a)}^{2} }

 = \frac{1}{( - {a })^{2} } \\ =  \frac{1}{ {a}^{2} }

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Answered by bharti7267
2
mark as brainliest plzzz

 \frac{ lim}{x - > 0} \: \: \: \: \frac{1}{(x - a) {}^{2} } \\ if \: x \: becomes \: 0 \: then \\ = \frac{1}{( - a) {}^{2} } \\ = \frac{1}{a {}^{2} } answer
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