Question

lim x tends 2. x^3_4x^2+4x÷x^2_4

Answer 1

you can see your answer

Answer 2

Given,

$=\lim_{x \to 2 \ \ ( \frac{x^{3} - 4x^{2} + 4x}{x^{2} - 4})} \\ \\ = \lim_{x \to 2 \ \ ( \frac{x(x^{2} -4x + 4 )}{x^{2} - 2^{2}}) \ \\ </p><p>\\=\lim_{x \to 2 \ \ \frac{x(x-2)^{2}}{(x-2)(x+2)} \\</p><p>\\ =\lim_{x \to 2 \ \ \frac{x(x-2)}{(x+2)}$

= 2(2-2)/(2+2)

= 0