lim x tends to 0 (1-cos^3x)/xsin2x
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Lim( x→0) { 1- cos³x}/xsin2x
here ,
( 1 - cos³x) = (1 -cosx)(1 + cos²x + cosx)
= (2sin²x/2)( 1 + cos²x + cosx)
and use concept ,
Lim( x → 0) sinx/x = 1
now,
Lim ( x →0) (2sin²x/2/x²/4 × x²/4 )( 1 + cos²x + cosx)/x(sin2x/2x) ×2x
= ( 2× 1/4) ( 1+ 1 + 1)/( 2)
= 3/4 ( answer )
here ,
( 1 - cos³x) = (1 -cosx)(1 + cos²x + cosx)
= (2sin²x/2)( 1 + cos²x + cosx)
and use concept ,
Lim( x → 0) sinx/x = 1
now,
Lim ( x →0) (2sin²x/2/x²/4 × x²/4 )( 1 + cos²x + cosx)/x(sin2x/2x) ×2x
= ( 2× 1/4) ( 1+ 1 + 1)/( 2)
= 3/4 ( answer )
abhi178:
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