lim x tends to 0 (1+cos 4x)(1-cos3x)/x^2 =?
Answers
Answered by
0
Answer:
The series expansion of
cos
(
α
x
)
for
x
=
0
in an open set containing
0
is given by
∞
∑
i
=
0
(
−
1
)
i
(
α
x
)
2
i
2
n
!
Then
1
−
cos
(
4
x
)
=
8
x
2
−
32
x
4
3
+
256
x
6
45
+
...
also
1
−
cos
(
3
x
)
=
9
x
2
2
−
27
x
4
8
+
81
x
6
80
+
...
so
1
−
cos
(
4
x
)
=
x
2
(
8
−
32
x
2
3
+
256
x
4
45
+
...
)
also
Answered by
0
Answer:
lim x tends to 0 (1+cos 4x)(1-cos3x)/x^2 =?
Attachments:
Similar questions