Question

lim x tends to 0 1-(cosx)(cos2x)(cos3x)÷sin^2 2x

Answer 1

Answer:

Since the limit results in the indeterminate form 0/0, the key here is to apply L'hopital rule multiple times until the limit can be defined by differentiating trigonometric functions on both numerator and denominator. The final answer should be 7/4 or 1.75.

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Step-by-step explanation: