lim x tends to 0: 2|sinx| / x
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2sin(h+0)/h+0
2sinh/h
2sin1
2×π\2
2×1
2
2sinh/h
2sin1
2×π\2
2×1
2
Answered by
0
not defined because LHL is -2 while RHL is 2 ..
since limits are not equal thus it doesn't exist .
for x<0 |sinx| equals -sinx
LHL
= -2sinx/x= -2
RHL
2sinx/x=2
since limits are not equal thus it doesn't exist .
for x<0 |sinx| equals -sinx
LHL
= -2sinx/x= -2
RHL
2sinx/x=2
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