Question

lim x tends to 0 (e^3x -5x)^1/x​

Answer 1

Answer:

$lim_{x - > 0}( { e}^{ \frac{1}{x} ( {e}^{3x} - 5x - 1)} ) = lim_{x - > 0}( {e}^{ \frac{3 {e}^{3x} - 5 }{1}) } ) = 3 - 5 = - 2$