Question

lim x tends to 0 find 1-sinx/ cosx​

Answer 1

Answer:

Hi Friend

Step-by-step explanation:

limx→0 (1−sin(x))cosxx=limx→∞ (1−sin(1x))cos1x1x≈

limx→ ∞ (1−1x)cos1x1x= limx→ ∞ (1−1x)cos1x⋅x=

eaxlog(c)+abc

with a=cos1x; b=−1; c=1; so

eaxlog(c)+abc=e1⋅x⋅log(1)+−1⋅11=e1⋅x⋅0+−1⋅11=e1⋅x⋅0−1=e0−1=e−1.

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