Question

lim x tends to 0 secx-1/x^2​

Answer 1

Answer:

0

Step-by-step explanation:

Lt (secx - 1 )/x² (is 0/0)

x->0

use, L' Hospital rules

Lt secx.tanx/2x (is 0/0)

x->0

again, use L' Hospital rules

Lt (secx.sec³x+secx.tanx.tanx)/2

x->0

= (sec³0+sec0.tan²0)/2 = 0/2 = 0.