Question

lim x tends to 0( sinx-2sin3x+sin5x)/x

Answer 1

hello users .....
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we have to find :
lim x→ 0 (sin x -2 sin 3x + sin 5x) / x = ?

solution:-
we know that:-
lim x→ 0 { (sin x) / x} = 1

=> lim x→ 0 (sin x -2 sin 3x + sin 5x) / x

= lim x→ 0 [ (sin x)/x - 2 (sin 3x)/x + (sin 5x) / x ]

=> lim x→ 0 (sin x)/x - 2 lim x→ 0 (sin 3x)/x + lim x→ 0 (sin 5x) / x

=> lim x→ 0 (sin x)/x - 2 lim x→ 0 3 (sin 3x)/3x + lim x→ 0 5(sin 5x) / 5x

=> lim x→ 0 (sin x)/x - 6 lim x→ 0 (sin 3x)/3x + 5 lim x→ 0 (sin 5x) / 5x

=> 1 -(6×1) +(5×1 )

=> 6-6 = 0 Answer

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⭐ hope it helps :)

Answer 2

Answer:

Step-by-step explanation:

I hope it helps....