Question

lim x tends to 1 4x³-2x²+x-3/x-1​

Answer 1

Answer:

Step-by-step explanation:

Step-by-step explanation:

we have to find quotient and remainder when 4x³ + 2x² + 5x - 6 is divided by 2x² + 3x + 1.

so, Let's start to divide !

2x² + 3x + 1 ) 4x³ + 2x² + 5x - 6(2x -2

4x³ + 6x² + 2x

---------------------------

-4x² + 3x - 6

-4x² - 6x - 2

-------------------

9x - 4

hence quotient = 2x - 2

Answer 2

Step-by-step explanation:

On directly applying the limit we get the indeterminate form 0/0

Hence we can apply the L-Hospital rule

ie. differentiating both numerator and denominator wrt x

lim x tends to 1 (12x^2 - 4x + 1) / 1

Applying the limit we get

= (12 - 4 + 1)/1

= 9