lim x tends to 1 (x/x-1 -1/lnx)
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Answer:
Write everything in an accurate way:
xxx−1=exp((logx)(xx−1))=exp(xlog2x(exlogx−1xlogx))
Now, since limh→0eh−1h=1 and limx→0xlog2x=0 you get that the whole limit is
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