Question

Lim x tends to 2 sin(x-2)/3x-6

Answer 1

= lim. sin(x-2)/3x-6
x-->2

= lim. cos(x-2)/3(1)-0
x-->2

= lim. cos(x-2)/3
x-->2

= cos(2-2)/3

= cos(0)/3

>>hint cos(0) = 1

= 1/3

hence proved