lim x tends to π/2 tan5x/tanx
Answers
Answered by
12
lim (x ->0) pi/2 tan5x/tanx =
lim (x ->0) pi/2 (sin5x/sinx)*(cosx/cos5x)
lim (x ->0) pi/2 (sin5x/sinx) | h'ospital rule |
lim (x ->0) pi/2 (5*cos5x/cosx) = 5π/2
lim (x ->0) pi/2 (sin5x/sinx)*(cosx/cos5x)
lim (x ->0) pi/2 (sin5x/sinx) | h'ospital rule |
lim (x ->0) pi/2 (5*cos5x/cosx) = 5π/2
Answered by
25
The limit is equal to or 0.2.
Step-by-step explanation:
Given:
The limit is given as:
We know,
∴
Therefore, the limit is equal to or 0.2.
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