Question

lim x tends to π/2 (tanx-2xsecx/π)
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Answer 1

Answer:

Lim x -> (pi / 2) (sec (x) - tan (x)) lim x -> pi / 2 ((1-sin x) / cos x) = lim x -> pi / 2 ( (1-sin x) (cos x)) / cos ^ 2 x = lim x -> pi / 2 ((1-sin x) cos x) / (1-sin ^ 2 x) = lim x -> pi / 2 (1-sin x) (cos x) / ((1-sin x) (1 + sin x)) = lim x -> pi / 2 ((cos x) / (1 + sin x)) = cos (pi / 2) / ((1+ sin (pi / 2)) = 0 / (1 + 1) = 0 = CO