lim x tends to 2 :- then x^3-2x^2/x^2-5x+6
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= (x-2) × x^2/(x-2) × (x-3)
as x tends to 2 implies x is not equal to 2 therefore x-2 can be cancelled
we have to do this because 0/0 is indeterminable form
ans 4/1= 4
as x tends to 2 implies x is not equal to 2 therefore x-2 can be cancelled
we have to do this because 0/0 is indeterminable form
ans 4/1= 4
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