Question

lim x tends to 3 : (1/x-3) - (9x/x³-27)

Answer 1

here's the answer in the picture

Answer 2

$(\frac{1}{x-3} - \frac{9x}{x^{3} - 27} ) | _{x}^{3} \\ \frac{x-3}{x^{2} + 3x + 9}| _{x}^{3} = 0$