Question

lim x tends to 3 ( ( x-1)/(2x^6-7x+5)

Answer 1

Hi perform a polynomial division.
i.e. Denominator ÷ Numerator
I have done it for you. Please find the attachment.
Then the function will look like below
$\frac{x - 1}{2 {x}^{6} - 7x + 5} = \frac{x -1}{(x - 1)(2 {x}^{5} + 2 {x}^{4} + 2 {x}^{3} + 2 {x}^{2} + 2x - 5) } = \\ \frac{1}{2 {x}^{5} + 2 {x}^{4} + 2 {x}^{3} + 2 {x}^{2} + 2x - 5 }$
Now perform the limit operation.
You will get it as 1/721.