Question

lim x tends to 3 x3-27/x-3

Answer 1

Lim x tends to 3
Function: (x^3-27)/(x-3)
So,
x^3-27
=x^3-(3)^3
By formula
a^3-b^3=(a-b)(a^2-ab+b^2)
x^3-(3)^3=(x-3)(x^2-3x+9)
So,lim x tends to 3
Function :
=x^3-27/(x-3)
=x^3-(3)^3/(x-3)
=(x-3)(x^2-3x+9)/(x-3)
=(x^2-3x+9)
Substituting x=3
Answer:
3^2-3x3+9
=9+9-9
=9
That's all!!!

Answer 2

The answer is 27

• If we substitute x = 3 in the given function, we get

                 $\frac{27-27}{3-3}  = \frac{0}{0}$

         which is indeterminate

• Hence, we will try evaluating the limit by factorizing the given polynomial.