Question

lim x tends to 4 [(3-√(5-x))/(1-(√5-x))] evaluate the limit... see the pic

Answer 1

answer is 1/3

lim(x → 4) [3 - √(5 + x)]/[1 - √(5 - x)]

putting x = 4, we get form of limit 0/0.

so, we can apply L - Hospital rule,

differentiating numerator and denominator individually.

lim(x → 4) [0 - 1/2√(5 + x) × 1]/[0 - 1/2√(5 - x) × -1]

= lim(x → 4) [1/√(5 + x)]/[1/√(5 - x)]

= lim (x → 4) √(5 - x)/√(5 + x)

= √(5 - 4)/√(5 + 4)

= 1/3

also read similar questions: limit x tends to 4 √(x+5) -3 ÷ x-4

https://brainly.in/question/11527693

Lim x tends to π/4 (4√2-(cos x + sin x)^5)/1- sin2x

https://brainly.in/question/1096831

Limit x tends to 0 1-√cos x/ x^2 evaluate the limit

https://brainly.in/question/1382314