Question

lim x tends to infinity ((ax+1)/(ax-1) ^x

Answer 1

Step-by-step explanation:

as if we put x as infinity we will get infinity/infinity form or 1/0/1/0 from and so ((ax+1)/(ax-1)^x) and can be written as (1/(ax-1)^x)/(1/(ax+1)) as it is now 0/0 form use L hospital rule and take derivative of numerator and put and same for denominator

Answer 2

Answer:

Step-by-step explanation:

e^2/