Question

lim x tens to 0 log ( 1 -7x)/5x​

Answer 1

Step-by-step explanation:

$\lim_{x \rarr0 } \frac{ log(1 + 7x) }{5x}$

$\lim_{x \rarr0 } \frac{ log(1 + 7x) }{7x} . \frac{7x}{5x}$

$\lim_{x \rarr0 } \frac{ log(1 + 7x) }{7x} \times \lim_{x \rarr0 } \frac{7x}{5x}$

$= 1 \times \lim_{x \rarr0 } \frac{7}{5}$

$= \frac{7}{5}$